1 Infinite Limits

Before we cover any material from this week, its worth discussing the use of \infty as a limit, especially when applying the Algebra of Limits. The main thing to note is that expressions such as \infty - \infty and \frac{\infty}{\infty} don’t really make a lot of sense, for example:

Example 1.1:

Give examples of sequences (a_n)_{n\in\mathbb{N}} and (b_n)_{n\in\mathbb{N}}, both diverging to \infty for which:

  1. (a_n - b_n)_{n\in\mathbb{N}} diverges to \infty,
  2. (a_n - b_n)_{n\in\mathbb{N}} diverges to -\infty, and
  3. (a_n - b_n)_{n\in\mathbb{N}} converges to 0.
Solution.

The idea here is to look for fairly simple sequences. With that in mind:

  1. If we take a_n = 2n and b_n = n, we see that a_n - b_n = n, and (n)_{n\in\mathbb{N}} diverges to \infty. But if we tried to apply the algebra of limits to this result, it would suggest that \infty - \infty = \infty.
  2. If we take a_n = n and b_n = 2n, we see that a_n - b_n = -n, and (-n)_{n\in\mathbb{N}} diverges to -\infty. But, again, if we tried to apply AoL to this result, it would suggest that \infty - \infty = -\infty. Immediately this conflicts with the answer to part 1)!
  3. Finally, if we take a_n = b_n = n, we see that a_n - b_n = 0, and (0)_{n \in \mathbb{N}} is a convergent sequence — it converges to 0. Attempting to apply AoL to this result suggests that \infty - \infty = 0.

What parts 1), 2) and 3) demonstrate is that you can’t consistently define \infty - \infty. (Note: if you take the same sequences from 1), 2) and 3) and divide them, you can see why \frac{\infty}{\infty} isn’t consistently define-able either).