1.1 Sequences
1.1.1 Two Useful Theorems
Last week, we were introduced to the idea of sequences and what it means for a sequence to converge. The definition of this is repeated below.
Using this definition, we can establish two theorems which will really help us when looking for further results about sequences.
Let \((a_n)_{n\in\mathbb{N}}\) and \((b_n)_{n\in\mathbb{N}}\) be sequences and let \(L,M \in \mathbb{R}\) be such that \(a_n \to L\) and \(b_n \to L\) as \(n \to \infty\). If \(a_n \leq b_n \; \forall n \in \mathbb{N}\), then \(L \leq M\).
Let \((a_n)_{n\in\mathbb{N}}\) and \((b_n)_{n\in\mathbb{N}}\) be sequences and let \(L,M \in \mathbb{R}\) be such that \(a_n \to L\) and \(b_n \to L\) as \(n \to \infty\). If \(a_n < b_n \; \forall n \in \mathbb{N}\), then \(L < M\).
To see why this is false, consider the sequences defined by \(a_n = 1 - \frac{1}{n}\) and \(b_n = 1\). We note that each \(a_n\) is strictly less than each corresponding \(b_n\), but we find that \[\lim_{n \to \infty} a_n = 1 = \lim_{n \to \infty} b_n.\]
The second reason why Theorem 1.1 is so important, is that it gives us this second theorem1:If \((a_n)_{n\in\mathbb{N}}\) is convergent with \(a_n \to L\) and \(a_n \to M\) as \(n \to \infty\), then \(L = M\).
1.1.2 Bounded Sequences
Much like we have done with sets, we can formulate a definition which allows us to ‘trap’ sequences.
If you prefer to think diagramatically, this says we can trap the sequence within a strip of width \(2M\) centred round \(0\). More importantly, this leads to the idea that all convergent sequences are bounded. Note that this is equivalent to saying that if a sequence is not bounded, then it is not convergent.
1.1.3 Algebra of Limits
Using the definition to prove all limits would be an incredibly boring way to go through this course. Luckily, there are a few general results we can prove which make our lives so much easier. This is known as the algebra of limits (AoL).
Let \(A,B,c \in \mathbb{R}\) and let \((a_n)\) and \((b_n)\) be sequences with \(a_n \to A\) and \(b_n \to B\) as \(n \to \infty\). Then:
- \(\lim_{n \to \infty} (a_n + b_n) = A + B\),
- \(\lim_{n \to \infty} (ca_n) = cA\),
- \(\lim_{n \to \infty} (a_n b_n) = AB\),
- If \(b_n \neq 0 \; \forall n \in \mathbb{N}\) and \(B \neq 0\), \(\lim_{n \to \infty} \frac{a_n}{b_n} = \frac{A}{B}\).